...

Equation has solutions for

$$\begin{eqnarray*}((I_1^1, I_2^1), (I_1^2, I_2^2)) & = & ((0,0), (1,0)), \\ & =... ...3), (1,3)), \\ & = & ((1,3), (2,3)), \\ & = & ((2,3), (3,3)) \end{eqnarray*}$$

We can summarise this by saying that the dependence distance vector for this dependence is

(I₁²-I₁¹, I₂²-I₂¹)

that is, (1,0).

This corresponds to a dependence direction vector (<,.): there is a loop-carried data dependence in the outer loop.