forThere are two potential dependences arising from the three references to A.= 0 to 3 do
for
= 0 to 3 do
S: A[
,
]
Consider the dependence equations:
for
S: A[
for
There are two potential dependences arising from the three references to A.
= 0 to 3 do
= 0 to 3 do
, ] := A[ , ] + A[ , ]
Therefore two systems of dependence equations to solve:
((strictly we should also consider output dependences between A[
, 
] and A[ 
, 
], but this is
obviously absent)).
, 
]:
